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5=-5t^2+3t+2
We move all terms to the left:
5-(-5t^2+3t+2)=0
We get rid of parentheses
5t^2-3t-2+5=0
We add all the numbers together, and all the variables
5t^2-3t+3=0
a = 5; b = -3; c = +3;
Δ = b2-4ac
Δ = -32-4·5·3
Δ = -51
Delta is less than zero, so there is no solution for the equation
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